Area of Path and Verandah
Area of Path and Verandah
Area of Path & Verandah:
It is observed that in square or rectangular gardens or parks. Some space in the form of path is left inside or outside or in between as cross paths.
Illustration: A footpath of uniform width 5 m runs round the inside of a rectangular park 38 m long and 32 m wide. Find the area of the path.
Solution: Let ABCD be the rectangular park and PQRS be the internal boundaries of the path.
We have, Length AB= 38 m and Breadth BC= 32 m:
Thus, Area of rectangle ABCD = AB BC = 38 m
32 m = 1216
Now, Length PQ = 38 m - 5 m - 5 m = 28 m and Breadth QR = 32 m - 5 m - 5 m = 22m
Area of rectangle PQRS = PQ RS = 28 m
22 m = 616
Area of footpath = Area of rectangle ABCD - Area of rectangle PQRS = 1216 - 616=600
Thus, Area of footpath =600
The area of the crossroads = Area of the two colored rectangles - Area of the red colored rectangle at the centre.
We are subtracting the area of the rectangle because we are taking it into consideration two times.
A square plot has side 100 m. A path 5 m wide runs breadth wise across the ground in the middle. Find the area of the path. | |||
| Right Option : A | |||
| View Explanation | |||
A square lawn is surrounded by a path 3 m wide. If the area of the path is 360 sq m. Find the area of the lawn. | |||
| Right Option : A | |||
| View Explanation | |||
A painting is painted on a cardboard 19 cm and 14 cm wide , such that there is a margin of 1.5 cm along each of its sides .Find the total area of the margin. | |||
| Right Option : A | |||
| View Explanation | |||
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